Tìm số phức \(\bar z\) thỏa mãn \(\frac{{2 + i}}{{1 - i}}z = \frac{{ - 1 + 3i}}{{2 + i}}\)

Tìm số phức \(\bar z\) thỏa mãn \(\frac{{2 + i}}{{1 - i}}z = \frac{{ - 1 + 3i}}{{2 + i}}\)
A. \(\frac{{22}}{{25}} + \frac{4}{{25}}i\)
B. \(\frac{{22}}{{25}} - \frac{4}{{25}}i\)
C. \(\frac{{22}}{{25}}i + \frac{4}{{25}}\)
D. \( - \frac{{22}}{{25}} + \frac{4}{{25}}i\)

Ta có:
\(\frac{{2 + i}}{{1 - i}}z = \frac{{ - 1 + 3i}}{{2 + i}} \Rightarrow z = \frac{{\left( { - 1 + 3i} \right)\left( {1 - i} \right)}}{{{{\left( {2 + i} \right)}^2}}}\)
\( = \frac{{\left( { - 1 + 3i} \right)\left( {1 - i} \right){{\left( {2 - i} \right)}^2}}}{{25}} = \frac{{22}}{{25}} + \frac{4}{{25}}i\)