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Cho \({\log _{14}}7 = a,\,{\log _{14}}5 = b\). Tính \({\log _{35}}28\) theo a, b.
A. \({\log _{35}}28 = \frac{{1 - a}}{{a - b}}\)
B. \({\log _{35}}28 = \frac{{2 - a}}{{a + b}}\)
C. \({\log _{35}}28 = \frac{{2 + a}}{{a - b}}\)
D. \({\log _{35}}28 = \frac{{1 - a}}{{a + b}}\)
A. \({\log _{35}}28 = \frac{{1 - a}}{{a - b}}\)
B. \({\log _{35}}28 = \frac{{2 - a}}{{a + b}}\)
C. \({\log _{35}}28 = \frac{{2 + a}}{{a - b}}\)
D. \({\log _{35}}28 = \frac{{1 - a}}{{a + b}}\)