Nguyễn Thị Thanh Thảo
New member
Tính \(z = \frac{{1 + 3i}}{{2 - i}}\)
A. \(z = \frac{-1}{5} + \frac{{7i}}{5}\)
B. \(1+i\)
C. \(z = \frac{1}{5} - \frac{{7i}}{5}\)
D. \(1-i\)
A. \(z = \frac{-1}{5} + \frac{{7i}}{5}\)
B. \(1+i\)
C. \(z = \frac{1}{5} - \frac{{7i}}{5}\)
D. \(1-i\)