Tuyền Thanh
New member
Cho ánh xạ tuyến tính \(f(x,y,z) = (x + 3y + 4z,x - 7z)\) thì ma trận chính tắc của nó là:
A. \(A = \left( \begin{array}{l}
\begin{array}{*{20}{c}}
1&1\\
3&0
\end{array}\\
4\,\,\,\, - 7
\end{array} \right)\)
B. \(A = \left( {\begin{array}{*{20}{c}}
1&{3\,\,\,\,\,4}\\
1&{0\,\,\,\,\, - 7}
\end{array}\,\,\,} \right)\)
C. \(A = \left( {\begin{array}{*{20}{c}}
2&{ - 1}\\
{ - 8}&4
\end{array}} \right)\)
D. \(A = \left( {\begin{array}{*{20}{c}}
2&{ - 1\,\,\,\,\,\,4}\\
{ - 8}&{4\,\,\,\,\,\,\,\, - 7}
\end{array}} \right)\)
A. \(A = \left( \begin{array}{l}
\begin{array}{*{20}{c}}
1&1\\
3&0
\end{array}\\
4\,\,\,\, - 7
\end{array} \right)\)
B. \(A = \left( {\begin{array}{*{20}{c}}
1&{3\,\,\,\,\,4}\\
1&{0\,\,\,\,\, - 7}
\end{array}\,\,\,} \right)\)
C. \(A = \left( {\begin{array}{*{20}{c}}
2&{ - 1}\\
{ - 8}&4
\end{array}} \right)\)
D. \(A = \left( {\begin{array}{*{20}{c}}
2&{ - 1\,\,\,\,\,\,4}\\
{ - 8}&{4\,\,\,\,\,\,\,\, - 7}
\end{array}} \right)\)