Cho \({\log _{27}}5 = a,\,{\log _8}7 = b,{\log _2}3 = c\). Biểu diễn \({\log _{12}}35\) theo a, b, c.
A. \({\log _{12}}35 = \frac{{3b + 3ac}}{{c + 2}}\)
B. \({\log _{12}}35 = \frac{{3b + 2ac}}{{c + 2}}\)
C. \({\log _{12}}35 = \frac{{3b + 2ac}}{{c + 3}}\)
D. \({\log _{12}}35 = \frac{{3b + 3ac}}{{c + 1}}\)
A. \({\log _{12}}35 = \frac{{3b + 3ac}}{{c + 2}}\)
B. \({\log _{12}}35 = \frac{{3b + 2ac}}{{c + 2}}\)
C. \({\log _{12}}35 = \frac{{3b + 2ac}}{{c + 3}}\)
D. \({\log _{12}}35 = \frac{{3b + 3ac}}{{c + 1}}\)