Hoàng Thị Hương
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: Tính các tổng sau: ${{S}_{1}}=C_{n}^{0}+\dfrac{1}{2}C_{n}^{1}+\dfrac{1}{3}C_{n}^{2}+…+\dfrac{1}{n+1}C_{n}^{n}$
C. $\dfrac{{{2}^{n+1}}+1}{n+1}$
B. $\dfrac{{{2}^{n+1}}-1}{n+1}$
C. $\dfrac{{{2}^{n+1}}-1}{n+1}+1$
D. $\dfrac{{{2}^{n+1}}-1}{n+1}-1$
C. $\dfrac{{{2}^{n+1}}+1}{n+1}$
B. $\dfrac{{{2}^{n+1}}-1}{n+1}$
C. $\dfrac{{{2}^{n+1}}-1}{n+1}+1$
D. $\dfrac{{{2}^{n+1}}-1}{n+1}-1$